poisson process probability distribution

**emterics90** · April 20th 2006, 09:02 PM

A shop receives sales according to a Poisson process $\{N_t : t \ge 0\}$ with rate $\lambda=1$ per minute and suppose each sale, independently of the others, has probability 0.05 of being from a male and probability 0.95 of being from a female.

I'm trying to get the distribution of the number of females sales in the shop in the time interval $[0,t]$ .

I'm guessing you'd use a Poisson distribution. Someone told me you use an exponential distribution but the exponential is for the times between sales. So I am thinking that the fact that the sales have 0.95 probability of being female affects the rate $\lambda$ . So then x the number of female sales in the shop from 0 to t is distributed

$f(x)=\frac{e^{-0.95 \lambda t}(0.95 \lambda t)^x}{x!}$

Would this be right?

**CaptainBlack** · April 21st 2006, 04:13 AM

Originally Posted by emterics90

A shop receives sales according to a Poisson process $\{N_t : t \ge 0\}$ with rate $\lambda=1$ per minute and suppose each sale, independently of the others, has probability 0.05 of being from a male and probability 0.95 of being from a female.

I'm trying to get the distribution of the number of females sales in the shop in the time interval $[0,t]$ .

I'm guessing you'd use a Poisson distribution. Someone told me you use an exponential distribution but the exponential is for the times between sales. So I am thinking that the fact that the sales have 0.95 probability of being female affects the rate $\lambda$ . So then x the number of female sales in the shop from 0 to t is distributed

$f(x)=\frac{e^{-0.95 \lambda t}(0.95 \lambda t)^x}{x!}$

Would this be right?

Looks OK to me.

RonL

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