B throws 12 dice and wins if he scores at least two aces.
Find the probability:
So I was wondering if anyone could confirm or deny that
P(A) = 1 - (5/6)^12 - ((5/6)^11)(1/6)
Thanks
i hope you noticed that he used a binomial distribution method here. it might not have been what he thought about, but it's what he ended up using. the expression he has is 1 - Bin(12,0) - Bin(12,1), which is the probability of NOT rolling 0 aces or one ace, that is, at least two