Ok, I had a belt at this, here's what i have.

A = probability the the person has the disease (.05).

B = probability that the person hasn't got the disease (.95).

C = probability of detecting the disease if present (.95).

D = probability of detecting no disease if not present (.94).

P(person tests positive) = (0.05 * 0.95) + (0.95 * 0.06 (ŹD)) = 0.1045

So a person will test positive about 10% of the time, is this right or at least close to it??

And thank you Colby, you defo pointed me in the right direction

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