Pr(A) = 1/3
Pr(A') = 2/3
You must assume that there are a very large number of cards (why?).
I'll do (a) and (b) from first principles:
(a) The favourable sequence of events is A' A so you want Pr(A',A) = (2/3)(1/3) = 2/9.
(b) The favourable sequence of events is A or A' A so you want Pr(A or A',A) = 1/3 + 2/9 = 5/9.
(c) Basic formula: Mean = 1/p = 1/(1/3) = 3.
No offence chum but the questions you're posting are very routine and strongly indicate that you need to thoroughly revise this area of study, paying particular attention to worked examples. In particular, (c) requires only the simplest application of the basic formula ....