[CENTER] What is the formula for P^c(n,r) = ?

This formula goes along with P(n,r) = n!/(n-r)! and C(n,r) = n!/r!*(n-r)![CENTER]

I need to know this like now and it would be really nice for someone to answer this thank you.

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- Jan 3rd 2008, 11:43 AMAudriellaQuick and easy but like now urgent!
[CENTER] What is the formula for P^c(n,r) = ?

This formula goes along with P(n,r) = n!/(n-r)! and C(n,r) = n!/r!*(n-r)![CENTER]

I need to know this like now and it would be really nice for someone to answer this thank you. - Jan 3rd 2008, 11:53 AMJhevon
that is a very weird formula, why would you need to know that? P here represents the permutation formula?

it would be: $\displaystyle P_{(n,r)}^{C(n,r)} = \left[ \frac {n!}{(n - r)!}\right]^{n!/[r!(n - r)!]}$

which cannot really be simplified nicely, not from what i can see