Three men and three women line up at a checkout counter in a store.
a. In how many ways can they line up?
b. In how many ways can they line up if the first person in line is a woman, and then the line alternates by gender- that is a woman, a man, a woman, a man and so on?
c. Find the probability that the first person in line is a woman and the line alternates by gender.

***I'm really stuck on this one, and help would be appreciated!!!!****

2. $\begin{array}{l}
a)\;6! \\
b)\;\left( {3!} \right)^2 \\
\end{array}
$

Can you finish?

3. ## still don't get it

I'm still not understanding. How di you arrive at your answer, that's what I need to know.
Thanks

4. Originally Posted by bcelena
I'm still not understanding. How di you arrive at your answer, that's what I need to know.
Well then what do you know about arrangements?
How many way can we arrange "ABCD"
Is it (4)(3)(2)(1)=(4!)? Four ways to put a first one; three wats to put a second one; etc.

Now look back at the answers.

5. ## thanks

I figured it out, thanks for your help!