• Dec 6th 2007, 10:30 AM
bcelena
Three men and three women line up at a checkout counter in a store.
a. In how many ways can they line up?
b. In how many ways can they line up if the first person in line is a woman, and then the line alternates by gender- that is a woman, a man, a woman, a man and so on?
c. Find the probability that the first person in line is a woman and the line alternates by gender.

***I'm really stuck on this one, and help would be appreciated!!!!****
• Dec 6th 2007, 10:41 AM
Plato
$\begin{array}{l}
a)\;6! \\
b)\;\left( {3!} \right)^2 \\
\end{array}
$

Can you finish?
• Dec 8th 2007, 10:28 AM
bcelena
still don't get it
I'm still not understanding. How di you arrive at your answer, that's what I need to know.
Thanks
• Dec 8th 2007, 10:38 AM
Plato
Quote:

Originally Posted by bcelena
I'm still not understanding. How di you arrive at your answer, that's what I need to know.

Well then what do you know about arrangements?
How many way can we arrange "ABCD"
Is it (4)(3)(2)(1)=(4!)? Four ways to put a first one; three wats to put a second one; etc.

Now look back at the answers.
• Dec 8th 2007, 12:56 PM
bcelena
thanks
I figured it out, thanks for your help!