Originally Posted by

**Soroban** Hello, sunrise2007!

Your denominator is correct.

. . There are: .$\displaystyle 5^4 \:= \:{\color{red}625}$ possible assignments.

Two students will be assigned the same section.

. . There are: .$\displaystyle {4\choose2} = {\color{blue}6}$ ways to choose the two students.

. . They can be assigned to any of the 5 sections.

. . The other two students have: .$\displaystyle 4 \times 3 \:=\:{\color{blue}12}$ possible assignments.

Hence, there are: .$\displaystyle 6 \times 5 \times 12 \:=\:{\color{red}360}$ ways.

Therefore, the probability is: .$\displaystyle \frac{360}{625} \;=\;\boxed{\frac{72}{125}}$

your answer Mr.Soroban very logic

my answer was correct but it is mising the permutition of two student and how are the student that choosen from the group ,

is describtion correct ???

Thank you so much for every one....

sorry ,i have another problem

the problem is

**If P (A1) = 5 P (A2) , AC S.**

**P(A/A1)= 0.2 ,P(A/A2) = 0.3 **

**what is the value of P (A1 /A) ?**

i am trying to solve it but i can not find the relation between the rules...

**From the rules**

**P(A/A2)=P(A ∩A2)/P(A2)**

**0.3= P(A ∩A2)/P(A2)**

**P(A/A1)=P(A ∩A1)/P(A1)**

**0.2= P(A ∩A1)/P(A1)**

=** P(A ∩A1)/ 5 P(A2) **