# [SOLVED] Accuracy &amp; Error

• Nov 22nd 2007, 06:50 AM
cold-peak
[SOLVED] Accuracy &amp; Error
Hi Everyone,

Just a quick question regarding Accuracy & Error.

We have been doing this for a little while (University) and I'm slightly confused with one of the problems.

I am able to do something like this and achieve the working and answer:

Code:

```(7.3 ± 0.4) x (1.2 ± 0.6)    /    (5.4 ± 1.3) ie: 1.3 * 5.4 = 7.02 0.6/1.3 = 0.46 1.3/5.4 = 0.24 Square root of: 0.46^2 + 0.24^2 = 0.52 = 0.52 * 7.02 = 3.65 to take it out of fractional error form = (7 ± 3.6) / (5.4 ± 1.3) = 7/5.4 = 1.29 3.6/7 = 0.51 1.3/5.4 = 0.24 = square root of: 0.51^2 + 0.24^2 = 0.56 = 0.56 * 1.29= 0.7 (to take it out of fractional error form) ans = (1.3 ± 0.7) * 10^4 etc```
However, when presented with this, I am not sure how to approach it:

1. The problem statement, all variables and given/known data
Code:

`(102 ± 32)^5`
2. The attempt at a solution
I'm just not sure what to do to it... The answer is:
Code:

` (1.1 ± 0.8) * 10^10`
Just not sure how to get there, any help?

EDIT: SOLVED - Was being silly!
• Nov 24th 2007, 12:53 AM
CaptainBlack
Quote:

Originally Posted by cold-peak
Hi Everyone,

Just a quick question regarding Accuracy & Error.

We have been doing this for a little while (University) and I'm slightly confused with one of the problems.

I am able to do something like this and achieve the working and answer:

Code:

```(7.3 ± 0.4) x (1.2 ± 0.6)    /    (5.4 ± 1.3)   ie: 1.3 * 5.4 = 7.02   0.6/1.3 = 0.46 1.3/5.4 = 0.24   Square root of: 0.46^2 + 0.24^2 = 0.52   = 0.52 * 7.02 = 3.65 to take it out of fractional error form   = (7 ± 3.6) / (5.4 ± 1.3)   = 7/5.4 = 1.29   3.6/7 = 0.51   1.3/5.4 = 0.24   = square root of: 0.51^2 + 0.24^2 = 0.56   = 0.56 * 1.29= 0.7 (to take it out of fractional error form)   ans = (1.3 ± 0.7) * 10^4 etc```
However, when presented with this, I am not sure how to approach it:

1. The problem statement, all variables and given/known data
Code:

`(102 ± 32)^5`
2. The attempt at a solution
I'm just not sure what to do to it... The answer is:
Code:

` (1.1 ± 0.8) * 10^10`
Just not sure how to get there, any help?

EDIT: SOLVED - Was being silly!

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