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**delso** A factory of 36 male workers and 64 female workers. worth 10 male workers earning less than \$1000 per month and 17 female workers earning at least \$1000 per month . At the end of year, workers earning less than \$1000 are given a bonus of \$1000 whereas others receive a month's salary.

If a male worker and a female worker are randomly chosen , find the probability that exactly one worker receive one month salary

here's my working.

P(male receive one month salary , female not receive one month salary) +P(female not receive one month salary , male receive one month salary) + P(female receive one month salary , male not receive one month salary) +P( male not receive one month salary , female receive one month salary

= (0.26 x (47/99)x2 ) + ( (0.17x (10/99) x2 ) = 0.28

but the ans is 0.604