Hi,
Could anyone suggest a way to compare the following two set of data
data 1 :
Mean average=54.7 gram
standard deviation = 1.1 gram
x=50
Data 2:
Mean average=50.3 gram
standard deviation = 3.7 gram
x=50
I have tried the normal distribution on the first set of data only to end up getting z score of -4.27 ,I can change this to positive but the z score table end with 3-4 maximum limit
Is there any other method to compare these two set of data?
Since the two sets of data are from different underlying distributions I can't agree with Shakarri.
If all you want to do is decide between the two distributions then simply select the one with the largest z-score.
$\left(\dfrac {50-54.7}{1.1}\right)=-4.27$
$\left(\dfrac{50-50.3}{3.7}\right)= -0.27$
$-0.27 > -4.27$ and thus it is more likely that your sample came from the second distribution.
The corresponding probabilities are
$Pr[-4.27] = 9.77x10^{-6}$
$Pr[-0.27] = 0.39$