I have an exercise stating what is written in the title-box.

"Cx on [0,3]"

I am not sure about what to do.

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- March 30th 2014, 01:15 AMkaemperProbability: Cx on [0,3]
I have an exercise stating what is written in the title-box.

"Cx on [0,3]"

I am not sure about what to do. - March 30th 2014, 01:48 AMromsekRe: Probability: Cx on [0,3]
The exercise gives you nothing else at all? No problems before this one establishing what Cx might be?

- March 30th 2014, 02:54 AMkaemperRe: Probability: Cx on [0,3]
Sorry

Attachment 30559

For part a I should solve z?

Attachment 30560 - March 30th 2014, 03:21 AMromsekRe: Probability: Cx on [0,3]
The function in your lower image is the Gaussian probability density function.

That page will tell you everything you need to know to answer your problem and more.

You need to learn this distribution as it is arguably the most important one there is. - March 30th 2014, 04:09 AMHallsofIvyRe: Probability: Cx on [0,3]
I see no reason to think that the given problem has anything to do with the Gaussian distribution you give below. The problem asks you to first find the value of "C" so that f(x)= Cx, is a probability distribution. The key point is the total probability, is equal to 1. So, do the integration, set it equal to 1, and solve for C.

For part (b), you are asked to find the mean, , and standard deviation, . The mean is the expected value of x itself, so is . The deviation is .

Once you have found those, part (c) is . (What you have written says that this is the probability the random variable, X, is**greater**than one standard deviation from the mean but, in fact, it is the probability it is**within**one standard deviation.)

But I am puzzled by your whole post. This is a fairly complicated problem, not requiring any difficult computation but certainly requiring that you understand several basic concepts. Yet, you seem to be saying that you do not know what**any**of the words in the problem mean! If, as you seem to be saying, you have never seen the idea that the total probability for a probability distribution must be 1, or what a "mean" or "standard distribution" are, I can't imagine why you were given a problem like this. - March 30th 2014, 04:46 AMkaemperRe: Probability: Cx on [0,3]
Thank you very much for this thoroughly worked-out answer. As I alluded above I had overlooked the set-up part. I have solved more simple tasks about mean and expectations.

- March 30th 2014, 05:21 AMromsekRe: Probability: Cx on [0,3]
I based my answer on the pictures in his 2nd post and ignored the content of the first post.