probability distribution help

Category: Tenure by household size (owner occupied plus renter occupied) Number of household members for state | Number of households in state with corresponding number of household members | Relative Frequency | | | |

1-person household | 732,263 | 28.7% | | μ | 363867.8571 |

2-person household | 813,166 | 31.9% | | Median | 353,676 |

3-person household | 417,216 | 16.4% | | Mode | None |

4-person household | 353,676 | 13.9% | | standard deviation | 291795.8781 |

5-person household | 150,842 | 5.9% | | | |

6-person household | 51,409 | 2.0% | | | |

7-or-more-person household | 28,503 | 1.1% | | | |

Total | 2,547,075 | | | | |

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Category Total Housing Units | Number of households in
state with corresponding # of rooms | Relative Frequency | | | |

1 room | 66,378 | 2.4% | | μ | 311,578 |

2 rooms | 80,730 | 2.9% | | Median | 323,335 |

3 rooms | 276,537 | 9.9% | | Mode | None |

4 rooms | 436,370 | 15.6% | | standard deviation | 161920 |

5 rooms | 512,146 | 18.3% | | | |

6 rooms | 500,359 | 17.8% | | | |

7 rooms | 345,510 | 12.3% | | | |

8 rooms | 262,841 | 9.4% | | | |

9 rooms or more | 323,335 | 11.5% | | | |

Total | 2,804,206 | | | | |

I'm not sure if i did the relative frequency,mean,median,mode,standard deviation can someone take a look and im not sure about unusual values? Also what type of graph would be apporiate for this data a histogram? help would be very much appreciated!(Nod)

Re: probability distribution help

You are doing your calculations with the wrong figures. The category is what you want to find the mean of. For your first set of data where the categories are 1,2,3... 7 and the frequency of the i^{th} category is f_{i} the mean is

The median is the value of i where 50% of the samples are less than or equal to i.

The mode is the value of i which is most common.

The variance can be calculated as

Re: probability distribution help

i thought you had to use households category then divide by how many rooms