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Math Help - urgent

  1. #1
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    urgent

    • The personnel department of a company has records which show the following analysis of its 200 engineers.

    Age
    Bachelor Degree
    Master Degree
    Total
    Under 30
    90
    10
    100
    30 to 40
    20
    30
    50
    Over 40
    40
    10
    20
    Total
    150
    50
    200


    If one engineer is selected at random from the company, find

    1. The probability that he has only a bachelorís degree.
    2. The probability that he has a masterís degree, given that he is over 40.
    The probability that he is under 30, given that he has only a bache
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  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
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    645
    Hello, Ms Batool!

    The personnel department of a company has records
    which show the following analysis of its 200 engineers.

    \begin{array}{cccccccc}\text{Age} &|& \text{BS} &|& \text{MS} &|& \text{Total} & | \\ \hline \text{under 30} &|& 90 &|& 10 &|& 100 &| \\<br />
\text{ 30-40} &|& 20 &|& 30 &|& 50 &| \\ \text{over 40} &|& 40 &|& 10 &|& 20 &| \\ \hline \text{Total} &|& 150 &|& 50 &|& 200 &| \end{array}

    If one engineer is selected at random from the company, find:

    1. The probability that he has only a BS.
    2. The probability that he has an MS, given that he is over 40.
    3. The probability that he is under 30, given that he has only a BS.
    1.\;P(\text{BS}) \;=\;\frac{150}{200} \;=\;\frac{3}{4}

    2.\;P(\text{ MS }|\text{ over 40}) \;=\;\frac{P(\text{MS }\wedge\text{ over 40})}{P(\text{over 40})} \;=\;\dfrac{\frac{10}{200}}{\frac{20}{200}} \;=\;\frac{1}{2}

    3.\;P(\text{under 30 }|\text{ BS}) \;=\;\frac{P(\text{under 30} \wedge\text{ BS})}{P(\text{BS})} \;=\;\dfrac{\frac{90}{200}}{\frac{150}{200}} \;=\;\frac{3}{5}

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  3. #3
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    Hello Sir,
    I want to thank you for your help........thanks again for this usefull reply.
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