## Probability of dependent events

So I've got this problem:

From a group of 10 people (4 women and 6 men) 5 will be chosen randomly to occupy the following places in a committee:

1 president
1 vicepresident
3 council representatives

1. If 3 men were chosen to occupy the last 3 places in the committee, how many different councils could there be?
A.4 B.6 C.15 D.20

2. After choosing the 5 people, an observer realizes that, of the first 4 students chosen, 3 are female and 1 is male. The observer ascertains that the fifth student chosen will have:
A. 2 times the probability of being male instead of female
B. 2 times the probability of being female instead of male
C. 3 times the probability of being male instead of female
D. 3 times the probability of being female instead of male

3. The probability of choosing 2 men and 3 women is equal to the probability of choosing:
A. 4 men and 1 woman
B. 1 man and 4 women
C. 3 men, 2 women
D. 5 men and no women

I only know for sure the answer to the first question, by using combinations as follows:

6! / 3!(6-3)! = 6! / 3!3! = 20, thus D

But I can't quite figure out what to do about the other 2. I've got an exam for university this weekend and I'm pretty stressed out. Can you please help me?