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Math Help - Confusing Probability!

  1. #1
    Junior Member Kaloda's Avatar
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    Confusing Probability!

    What is the probability that a 93% FT shooter will make 9 FT out of 10 FTA?


    Confused ..
    Last edited by Kaloda; August 20th 2013 at 07:33 AM.
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  2. #2
    MHF Contributor ebaines's Avatar
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    Re: Confusing Probability!

    Given probability of success on any one free throw is p=0.93, the probability of geting exacty k free throws in n attemps is:

    P(\text{k\ success\ in \ n \ attempts}) = C(n,k)p^k(1-p)^{n-k}

    where C(n,k) is the number of combinations of k items in a set of n:

     C(n,k) = \frac {n!}{k!(n-k)!}

    So here you have:

    P(\text{9\ success\ in\ 10\ attempts}) = C(10,9)(0.93)^9(0.07)^1 = 0.3643
    Last edited by ebaines; August 20th 2013 at 08:16 AM.
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