1. Probability question

Hi,

I made a survey where n people answered several questions; one of the questions was "What is your sign?"
A person can be of one of the 12 signs of the zodiac.
My question is: what is the probability of x people of n be of one specific sign?

Kind regards,

Kepler

2. Re: Probability question

Originally Posted by kepler
I made a survey where n people answered several questions; one of the questions was "What is your sign?"
A person can be of one of the 12 signs of the zodiac.
My question is: what is the probability of x people of n be of one specific sign?
You must assume that this is binomial probability.
$\mathcal{P}(X=k)=\binom{N}{k}(p)^k(1-p)^{N-k}$ which means there are $k$ happenings in $N$ tries and $p$ is the probability is occurs.

So in your query, $N$ is the number of people you survey and $p=\tfrac{1}{12}~.$

3. Re: Probability question

Originally Posted by Plato
You must assume that this is binomial probability.
$\mathcal{P}(X=k)=\binom{N}{k}(p)^k(1-p)^{N-k}$ which means there are $k$ happenings in $N$ tries and $p$ is the probability is occurs.

So in your query, $N$ is the number of people you survey and $p=\tfrac{1}{12}~.$
Hi,

So, it's:

k!/(N!*(N-k)!)*(p^k)*((1-p)^(N-k))

?

Kind regards,

Kepler

4. Re: Probability question

Sorry...I mean:

N!/(k!*(N-k)!)*(p^k)*((1-p)^(N-k))

Kepler