The following data were sampled from a normally distributed population. At the 10% significance level, is there evidence to indicate that the mean of the population differs from 16?
12, 15, 14, 19, 15, 20, 16
remember this is a two tail test so rejection region(area) on both sides of norm curve will be .05,nw check ur sample and find your SAMPLE VARIANCE,then apply the standardization formula z=x-mu/sqrt(sample variance)
find p(x>16) find corresponding z value in N(0,1)and chk that value with z value for rejection region in this case 1.645 and then infer,hpe this helped