Results 1 to 2 of 2

Math Help - Help with "nCr" problems

  1. #1
    Newbie
    Joined
    May 2013
    From
    Ireland
    Posts
    4

    Help with "nCr" problems

    Can someone explain how to solve this problem please. "In how many ways can a team of 4 be chosen from 13 people if 2 of the people refuse to work on the same team?"
    Thanks in advance
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Oct 2012
    From
    Ireland
    Posts
    586
    Thanks
    155

    Re: Help with "nCr" problems

    If person A and person B will not work together there are 3 scenarios
    Case 1: Neither A nor B is chosen
    Case 2: A is chosen and B isn't
    Case 3: B is chosen and A isn't

    Find out how many ways a team can be formed in each case.

    Alternatively,
    The 4th and last case is that both are picked which isn't allowed. The number number of ways A and B are chosen together plus the sum of the ways in which they aren't chosen together is the total number of ways you can make a team of 4 without restrictions.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: April 2nd 2012, 07:06 PM
  2. Replies: 3
    Last Post: October 17th 2011, 02:50 PM
  3. Replies: 1
    Last Post: September 16th 2011, 01:08 AM
  4. Replies: 2
    Last Post: April 24th 2011, 07:01 AM
  5. Replies: 1
    Last Post: October 25th 2010, 04:45 AM

Search Tags


/mathhelpforum @mathhelpforum