Can someone explain how to solve this problem please. "In how many ways can a team of 4 be chosen from 13 people if 2 of the people refuse to work on the same team?"
Thanks in advance
If person A and person B will not work together there are 3 scenarios
Case 1: Neither A nor B is chosen
Case 2: A is chosen and B isn't
Case 3: B is chosen and A isn't
Find out how many ways a team can be formed in each case.
The 4th and last case is that both are picked which isn't allowed. The number number of ways A and B are chosen together plus the sum of the ways in which they aren't chosen together is the total number of ways you can make a team of 4 without restrictions.