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- Mar 12th 2006, 10:15 AMJonPlease help Urgent
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- Mar 12th 2006, 03:50 PMThePerfectHackerQuote:

Originally Posted by**Jon**

If the probability of an event is $\displaystyle p$ then the probability of that event happening $\displaystyle m$ out of $\displaystyle n$ times is,

$\displaystyle _nC_mp^n(1-p)^{n-m}$

In the problems when they are for at most. You need to add up all the probabilities. For example, at most 3: which means probability of exactly 0 plus probability of exactly 1 plus probability of exactly 2 plus probability of exactly 3.

The same with at least only in the other direction.