Here's the second one . . .
17. If and are disjoint, and , compute:
16 show that : p(A)+P(B)-1 ≤ P(A∩B) ≤ P(A)+P(B).
17. If A and B are disjoint P(A) =0.37 , P(B)= 0.44 , compute :
(a) P (A)=0.37
(b) P (B^c)=1-0.44=
(f) p (A^c∩B^c)=
18. if P(A) =0.59 ,P(B)= 0.3 , P(A∩B)=0.21 compute :
19 . show that the conditional probability satisfies the following
if P(B)>0 , then
i. P(A|B)≥ 0 ,
ii. P(B|B)=1 ,
for any sequence of disjoint events A1,A2,………..
for the second, i haven't solved yet.. Ü, but i think, it's just the same with the previous post..
or .... not sure..
same process with the fourth, apply de morgan's law..
but since and P(B)>0,
i dont understand the code for the third one..