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Math Help - Simple probability Q

  1. #1
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    Simple probability Q

    Hi guys,

    I came across this question, and couldnt figure out how he arrived at the answer. So i am hoping someone can help me...

    onsider a job interview situation to be a random experiment. Define two events: Event A : the candidate had good eye contact
    Event B : the candidate got the job.
    Assume that
    P(A) = 0.40
    P(B) = 0.20
    P(A and B) = 0.12

    P(A|B) = (P(A and B) / P(B) = 0.12 / 0.20 = 0.6
    P(B|A) = (P(A and B) / P(A) = 0.12 / 0.40 = 0.3

    Calculate the probability of candidate getting the job WITHOUT good eye contact?

    Supplied Ans:
    P(B|Not A) = P(B and Not A) / P(Not A) = 0.08 / 0.6 = 0.13


    How was P(B and Not A) = 0.08 calculated?
    Thanks for any help given....
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  2. #2
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    Re: Simple probability Q

    Notation: A^c is not A,

    \mathcal{P}(B)=\mathcal{P}(B\cap A)+\mathcal{P}(B\cap A^c)
    Thanks from ScorpFire
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  3. #3
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    Re: Simple probability Q

    Quote Originally Posted by Plato View Post
    Notation: A^c is not A,

    \mathcal{P}(B)=\mathcal{P}(B\cap A)+\mathcal{P}(B\cap A^c)
    Thank you SO much
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