onsider a job interview situation to be a random experiment. Define two events: Event A : the candidate had good eye contact

Event B : the candidate got the job.

Assume that

P(A) = 0.40

P(B) = 0.20

P(A and B) = 0.12

P(A|B) = (P(A and B) / P(B) = 0.12 / 0.20 = 0.6

P(B|A) = (P(A and B) / P(A) = 0.12 / 0.40 = 0.3

Calculate the probability of candidate getting the job WITHOUT good eye contact?

*Supplied Ans: *

P(B|Not A) = P(B and Not A) / P(Not A) = 0.08 / 0.6 = 0.13
How was P(B and Not A) = 0.08 calculated?