Results 1 to 5 of 5

Math Help - please check me answers

  1. #1
    Junior Member
    Joined
    Oct 2007
    From
    Egypt
    Posts
    35

    please check me answers

    1. P(A)=0.6 , P(B)=0.8 , P(A∩B)=0.5 ,compute :
    i. p(A^C∩B^C) =(1-0.6)+(1-0.8) - (1-0.5)
    =0.4+0.2-0.5
    =0.1

    i. P(B∩A^C) =[P(B)+(1-P(A))]
    = 0.8+(1-0.6)
    =0.8+0.4
    =1.2

    ii. P(A∩B^C) = P(A) P(A∩B)
    = 0.6-0.5
    = 0.1

    iii. P(A^CUB^C) =1-P(A∩B)
    =1- 0.5
    =0.5
    Last edited by compufatwa; October 31st 2007 at 11:34 AM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Global Moderator

    Joined
    Nov 2005
    From
    New York City
    Posts
    10,616
    Thanks
    9
    Do we know if these events are independent?

    P(A^C\cup B^C) = P(A\cap B)^C = 1 - P(A\cap B)

    P(B\cap A^C) = P(B^C \cup A)^C = 1 - P(B^C\cup A)
    Last edited by ThePerfectHacker; October 31st 2007 at 07:40 PM.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Oct 2007
    From
    Egypt
    Posts
    35
    is that rule is right (i mean the signs )
    P(AUB) = P(A)+P(B)-P(A intesection B)
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor kalagota's Avatar
    Joined
    Oct 2007
    From
    Taguig City, Philippines
    Posts
    1,026
    Quote Originally Posted by ThePerfectHacker View Post
    Do we know if these events are independent?

    P(A^C\cup B^C) = P(A\cup B)^C = 1 - P(A\cup B) = 1 - P(A) - P(B) + P(A\cap B)

    P(B\cap A^C) = P(B^C \cup A)^C = 1 - P(B^C\cup A)
    sir, i just noticed it, for the first one, should it be

    P(A^C\cup B^C) = P(A\cap B)^C
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Global Moderator

    Joined
    Nov 2005
    From
    New York City
    Posts
    10,616
    Thanks
    9
    Quote Originally Posted by kalagota View Post
    sir, i just noticed it, for the first one, should it be

    P(A^C\cup B^C) = P(A\cap B)^C
    Okay I fixed it now.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. I want check my answers
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: March 16th 2010, 08:40 AM
  2. check my answers plz
    Posted in the Calculus Forum
    Replies: 3
    Last Post: February 28th 2009, 06:06 PM
  3. Please check my answers
    Posted in the Algebra Forum
    Replies: 1
    Last Post: July 19th 2008, 02:48 AM
  4. Please check my answers
    Posted in the Calculus Forum
    Replies: 3
    Last Post: May 26th 2006, 07:53 AM
  5. I just want to check my answers, can you help me out?
    Posted in the Advanced Algebra Forum
    Replies: 2
    Last Post: April 27th 2005, 07:49 AM

Search Tags


/mathhelpforum @mathhelpforum