1. P(A)=0.6 , P(B)=0.8 , P(A∩B)=0.5 ,compute :

i.p(A^C∩B^C)=(1-0.6)+(1-0.8) - (1-0.5)

=0.4+0.2-0.5

=0.1

i.P(B∩A^C)=[P(B)+(1-P(A))]

= 0.8+(1-0.6)

=0.8+0.4

=1.2

ii.P(A∩B^C)= P(A) – P(A∩B)

= 0.6-0.5

= 0.1

iii.P(A^CUB^C)=1-P(A∩B)

=1- 0.5

=0.5