Originally Posted by
flashylightsmeow Sorry for the constant posts but this one is doing my head in. I can't find the answer to the 2nd part of e) a more direct way of finding the probability of being chosen for one of the parts
e) let A = being chosen for the heroine
B = being chosen for the best friend
then P(A u B) = 6/42 + 6/42 = 2/7
but what is the direct route for finding this probability? I thought perhaps I could use the rule 1 minus the complement of being being chosen...but then I dont know how to calculate the probability of not being chosen!