1. ## a combinations/permutations question

Hi all, another post...this question is confusing me.
I know there are 50 ways to select the first employee, then 49 ways for the 2nd.. so 50P2 or 50 x 49 =2450

Now I'm not sure how to deal with the remaining 48 as they all go into one group and since order doesnt matter isn't the calculation just 48C48 = 1

So I think the answer is simply 50P2 x 48C48 = 2450

many thanks!

2. ## Re: a combinations/permutations question

Originally Posted by flashylightsmeow
Hi all, another post...this question is confusing me.
I know there are 50 ways to select the first employee, then 49 ways for the 2nd.. so 50P2 or 50 x 49 =2450
Now I'm not sure how to deal with the remaining 48 as they all go into one group and since order doesnt matter isn't the calculation just 48C48 = 1
So I think the answer is simply 50P2 x 48C48 = 2450
It is really neither combinations nor permutations.
It is simply applying the principle of multiplication.
There are 50 ways to come first and 49 ways to come second.
$\displaystyle (50)(49)=~?$

3. ## Re: a combinations/permutations question

2450! Awesome thanks Plato!