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Math Help - a combinations/permutations question

  1. #1
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    a combinations/permutations question

    Hi all, another post...this question is confusing me.
    I know there are 50 ways to select the first employee, then 49 ways for the 2nd.. so 50P2 or 50 x 49 =2450

    Now I'm not sure how to deal with the remaining 48 as they all go into one group and since order doesnt matter isn't the calculation just 48C48 = 1

    So I think the answer is simply 50P2 x 48C48 = 2450

    But I also think I'm wrong! Please help!

    many thanks!
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  2. #2
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    Re: a combinations/permutations question

    Quote Originally Posted by flashylightsmeow View Post
    Hi all, another post...this question is confusing me.
    I know there are 50 ways to select the first employee, then 49 ways for the 2nd.. so 50P2 or 50 x 49 =2450
    Now I'm not sure how to deal with the remaining 48 as they all go into one group and since order doesnt matter isn't the calculation just 48C48 = 1
    So I think the answer is simply 50P2 x 48C48 = 2450
    But I also think I'm wrong! Please help!
    It is really neither combinations nor permutations.
    It is simply applying the principle of multiplication.
    There are 50 ways to come first and 49 ways to come second.
    (50)(49)=~?
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  3. #3
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    Re: a combinations/permutations question

    2450! Awesome thanks Plato!
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