# a combinations/permutations question

• Mar 27th 2013, 10:45 AM
flashylightsmeow
a combinations/permutations question
Hi all, another post...this question is confusing me.
I know there are 50 ways to select the first employee, then 49 ways for the 2nd.. so 50P2 or 50 x 49 =2450

Now I'm not sure how to deal with the remaining 48 as they all go into one group and since order doesnt matter isn't the calculation just 48C48 = 1

So I think the answer is simply 50P2 x 48C48 = 2450

many thanks!
• Mar 27th 2013, 12:27 PM
Plato
Re: a combinations/permutations question
Quote:

Originally Posted by flashylightsmeow
Hi all, another post...this question is confusing me.
I know there are 50 ways to select the first employee, then 49 ways for the 2nd.. so 50P2 or 50 x 49 =2450
Now I'm not sure how to deal with the remaining 48 as they all go into one group and since order doesnt matter isn't the calculation just 48C48 = 1
So I think the answer is simply 50P2 x 48C48 = 2450
$(50)(49)=~?$