1 Attachment(s)

a combinations/permutations question

Hi all, another post...this question is confusing me.

I know there are 50 ways to select the first employee, then 49 ways for the 2nd.. so 50P2 or 50 x 49 =2450

Now I'm not sure how to deal with the remaining 48 as they all go into one group and since order doesnt matter isn't the calculation just 48C48 = 1

So I think the answer is simply 50P2 x 48C48 = 2450

But I also think I'm wrong! Please help!

many thanks!

Re: a combinations/permutations question

Quote:

Originally Posted by

**flashylightsmeow** Hi all, another post...this question is confusing me.

I know there are 50 ways to select the first employee, then 49 ways for the 2nd.. so 50P2 or 50 x 49 =2450

Now I'm not sure how to deal with the remaining 48 as they all go into one group and since order doesnt matter isn't the calculation just 48C48 = 1

So I think the answer is simply 50P2 x 48C48 = 2450

But I also think I'm wrong! Please help!

It is really neither combinations nor permutations.

It is simply applying the *principle of multiplication*.

There are 50 ways to come first and 49 ways to come second.

$\displaystyle (50)(49)=~?$

Re: a combinations/permutations question

2450! Awesome thanks Plato!