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Math Help - Binomial distribution answe check

  1. #1
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    Binomial distribution answe check

    Hi, I'm very new to statistics and would like some one to check over the first part of the question i have done as well as some help on the other two parts.

    1) could some one please check part a and see if i have the correct answer .

    2) For the second part do i have to work out the probability of 6 machines failing then seven and eight etc all the way up to 60 and and the results together, so i will have a page full of calculations?

    3) i know i have to calculate Part b first but what exactly does the numbers mean in terms of the machines failing.

    Any help would be greatly appreciated.
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  2. #2
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    Re: Binomial distribution answe check

    Your answer to 1) is correct but 3.27 \times 10^{-3} is 0.327%

    For 2) find the chance that 6 machines will fail, and the chance 5 will fail, same for 4, 3, 2, 1, 0 machines and add up all the chances. That is the chance that 6 or less will fail. Remember that [chance 6 or less fail] + [chance more than 6 will fail] = 1
    Use this fact to find the chance that more than 6 will fail.

    Discuss your findings they probably just want you to talk about [chance 6 or less fail] + [chance more than 6 will fail] = 1 and how it is faster and still valid.
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  3. #3
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    Re: Binomial distribution answe check

    Yes, you answer for (a) is correct.

    2) For the second part do i have to work out the probability of 6 machines failing then seven and eight etc all the way up to 60 and and the results together, so i will have a page full of calculations?
    It will be a lot easier to find the probability that less than 6 machines will fail, then subtract from 1.

    I don't see any "part b" in your attachment.
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  4. #4
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    Re: Binomial distribution answe check

    Quote Originally Posted by djstar View Post
    Hi, I'm very new to statistics and would like some one to check over the first part of the question i have done as well as some help on the other two parts.

    1) could some one please check part a and see if i have the correct answer .

    2) For the second part do i have to work out the probability of 6 machines failing then seven and eight etc all the way up to 60 and and the results together, so i will have a page full of calculations?

    3) i know i have to calculate Part b first but what exactly does the numbers mean in terms of the machines failing.

    It looks correct to me. You can cheek it (60!/((5!)(55!))(.22)^(5)(.78)^(55) - Wolfram|Alpha.
    I do not see the rest of the question.
    What is the whole statement?
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  5. #5
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    Re: Binomial distribution answe check

    Thank you all for your kind replies, it makes sense to find the probability that less that 6 machines will fail and take it away from 1 I'll work that out in the next day and get you guys to check it please. Just one thing is how is 3.27 \times 10^{-3} 0.327% ???



    ps sorry about the part 'B' bit. part b was the question about 6 or more machines failing.
    Last edited by djstar; March 15th 2013 at 11:08 AM.
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  6. #6
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    Re: Binomial distribution answe check

    Quote Originally Posted by djstar View Post
    Just one thing is how is [tex]3.27 \times 10^{-3}/tex] 0.327% ???.
    3.27 \times 10^{-3}= 0.00327 this is in decimal form. To convert decimal to percentage multiply by 100.
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