I need help with the final step...

X~N(25,81)

Solve for:

P(24<X<43)

P(24<X<43) = P(24-25)/√81<(X-25)/9<(43-25)/9

P=(-1/9<Z<2) =ϕ(0,11) -ϕ2 = ???(Nod)

I would be grateful if anyone could help me!

Thanks!

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- Feb 21st 2013, 01:30 AMemme1The standard normal distribution
I need help with the final step...

X~N(25,81)

Solve for:

P(24<X<43)

P(24<X<43) = P(24-25)/√81<(X-25)/9<(43-25)/9

P=(-1/9<Z<2) =*ϕ(0,11) -**ϕ2 = ???*(Nod)

I would be grateful if anyone could help me!

Thanks! - Feb 21st 2013, 11:38 PMchiroRe: The standard normal distribution
Hey emme1.

Hint: P(-1/9 < Z < 2) = P(Z < 2) - P(Z < -1/9) where you can find these probabilities with either a computer or with statistical tables.

Have you done this before?