P(4) = 7/36
5choose 4 ((7/36)^4)(29/36) = .0057
so about one in 17543 attempts
What is the probability of rolling a pair of six-sided dice five times and getting four 4's?
@Plato this was the other questions I am really struggling with.
This is what I came up with, but I'm not sure if it is correct.
p(x=4) = C(5,4) × (1/36)^4 × (35/36)^5-4
which equals 2.894180045×10^-0.6 ....That looks wrong to me..?
p(x=4) = C(5,4) × (3/36)^4 × (33/36)
p(x=4) = 2.210326646×10^-04
My calculator is outputting a weird number?
OR is it NOT C(5,4) And just (5/4), which gives me 5.525816615×10^-05
___Compared to what my original post shows, I was only wrong with the probability of getting a 4. I had 1/36 and 35/36 WhereAs you have 3/36 and 33/36.
Once again -your a life saver man!
Thanks, that actually looks right, unlike the number I keep getting on my calculator?!?!?! *Don't Get WHY* I tried using an online calculator, input everything exactly the same and got 0.000221032664609.... Guess there's something wrong with my calculator! JUST VERY GLAD I finished those two questions!
0.000221032664609. ONLINE CALCULATOR
2.210326646×10^-04 MY CALCULATOR
^It seems as though it is just multiplying it a few thousand times? Why?