Probability of getting a cracked egg at the store is 7%:
a) What is the probability that a caron of 12 eggs will contain at LEAST one cracked egg? (hint: use indirect method to answer).
b) Determine the number of cracked eggs you expect to find in a gross of eggs? (A 'gross' is 12 dozen OR 144).
I am totally LOST . Would I be using Binomial Distribution with this formula: p(x)=C(n,x) · p^x · q^n-x
Thanks for you help! But I am still SO Lost!
For a) you said the probability of no cracked eggs is .
.........would I subtract that by 1 to get the probability of having at least one cracked egg?
.........how do I subtract that thing(decimal to a power) by 1?
.........how do I express a decimal to the power of something in a percentage?
For b) you said
........where p= probability of success and n=?