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Math Help - Help with CHI-SQUARE test and HYPOTHESIS

  1. #1
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    Help with CHI-SQUARE test and HYPOTHESIS

    I have a clinical trail where all the patients are suffering from a stroke.
    Half of the patients got drug and the other half got placebo.
    I need to assess the efficacy of the drug treatment for the entire sample by using the chi-square test in excel.
    I have the values if the treatment(drug/placebo) was a succes or a failure for each patient (attached file).
    My quesiton is what chi-square do i need to do in order to determine which drug is better? goodness-of-fit or independence?
    I think independence but im not sure...
    And also if anyone can help me with the null and the alternative hypothesis, cause i have no idea what to write :\
    THANKS A LOT!!!!
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  2. #2
    Super Member ILikeSerena's Avatar
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    Re: Help with CHI-SQUARE test and HYPOTHESIS

    Quote Originally Posted by eladgro View Post
    I have a clinical trail where all the patients are suffering from a stroke.
    Half of the patients got drug and the other half got placebo.
    I need to assess the efficacy of the drug treatment for the entire sample by using the chi-square test in excel.
    I have the values if the treatment(drug/placebo) was a succes or a failure for each patient (attached file).
    My quesiton is what chi-square do i need to do in order to determine which drug is better? goodness-of-fit or independence?
    I think independence but im not sure...
    And also if anyone can help me with the null and the alternative hypothesis, cause i have no idea what to write :\
    THANKS A LOT!!!!
    Hi eladgro!

    A goodness-of-fit is when you want to know if a set of frequencies matches a known distribution.
    Since you do not have a known distribution, you're not testing for goodness-of-fit.

    You do want to know if treatment and result are dependent or not.
    So indeed, you have a test for independence.

    H0: treatment and result are independent
    Ha: treatment and result are dependent

    You have a p-value of 0,000000062
    Typically you would test against an alpha of 0,05.
    So your result is significant.

    The statistical conclusion is that treatment with the drug has a significant effect on the success failure rate ( \chi^2(1), p = 0,000000062).
    Last edited by ILikeSerena; December 31st 2012 at 10:53 AM.
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    Re: Help with CHI-SQUARE test and HYPOTHESIS

    Thank you very much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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