Possible Geometric Distribution problem but I'm not sure...

I don't know what formula to use to solve this problem. It sounds like a Geometric Distribution but I'm not sure.

After repeated observations, it has been determined that the waiting time at the drive-through window of a local bank is skewed left, with a mean of 3.5 minutes and a standard deviation of 1.9 minutes. A random sample of 100 customers is to be taken. What is the probability that the mean of the sample will exceed 4 minutes?

The answer the teacher provided is 0.0042.

Thank you.

Hey yvonnehr.

If this is a waiting time that is continuous then you have might want to check the exponential distribution:

Exponential distribution - Wikipedia, the free encyclopedia

Quote:

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Originally Posted by yvonnehr

I don't know what formula to use to solve this problem. It sounds like a Geometric Distribution but I'm not sure.

After repeated observations, it has been determined that the waiting time at the drive-through window of a local bank is skewed left, with a mean of 3.5 minutes and a standard deviation of 1.9 minutes. A random sample of 100 customers is to be taken. What is the probability that the mean of the sample will exceed 4 minutes?

The answer the teacher provided is 0.0042.

Thank you.

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By the Central Limit Theorem, the mean is approximately Normal with mean 3.5 and a standard deviation of . (That the waiting time is skewed left is irrelevant.)

So what is the probability that a Normal random variable with mean 3.5 and standard deviation (as above) is greater than 4?