The expected value for the sum of the numbers on the upper faces of two fair dice, one "normal" die with the numbers 1, 2, 3, 4, 5, and 6 on its faces and one "special" die with the numbers 7, 8, 9, 10, 11, and 12 on its faces is what?

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- November 29th 2012, 08:06 AMgoldenrainexpected value
The expected value for the sum of the numbers on the upper faces of two fair dice, one "normal" die with the numbers 1, 2, 3, 4, 5, and 6 on its faces and one "special" die with the numbers 7, 8, 9, 10, 11, and 12 on its faces is what?

- November 29th 2012, 09:15 AMScopurRe: expected value
For the normal die let be the value of the upper face. Then takes on the values

So . So Let be the value on the second die. Calculate the expected value for that. Then use the independence of the rolls to calculate - November 29th 2012, 01:35 PMHallsofIvyRe: expected value
It's not that hard to do this directly: If the first roll is one, then the possible (and equally likely) totals are 1+ 7= 8, 1+ 8= 9, 1+ 9= 10, 1+ 10= 11, 1+ 11= 12, and 1+ 12= 13.

If the first roll is 2, the the possible totals are 2+ 7= 9, 2+ 8= 10, 2+ 9= 11, 2+ 10= 12, 2+ 11= 13, and 2+ 12= 14.

You can continue in the same way and see that there are 11 possible results, from 8 to 18. 8 occurs once, 9 occurs twice, 10 occurs 3 times, 11 occurs 4 times, 12 occurs 5 times, 13 occurs 6 times, 14 occurs 5 times, 15 occurs 4 times, 16 occurs 3 times, 17 occurs twice, and 18 occurs once.

That is a total of 36 outcomes so you can calculate the expected value.

Or you could do it the easy way: since "7, 8, 9, 10, 11, and 12" are just "1, 2, 3, 4, 5, 6", with 6 add. So find the expected value for the standard problem of rolling two dice and then add 6. - November 29th 2012, 02:51 PMSorobanRe: expected value
Hello, goldenrain!

Quote:

Two dice are rolled. One is "normal" with the numbers 1, 2, 3, 4, 5, 6 on its faces.

The other is "speial with the numbers 7, 8, 9, 10, 11, 12 on its faces.

Find the expected value for the sum of the numbers on the upper faces of the dice.

The sum will range from 8 to 18.

You can construct a 6-by-6 table to see the distribution of these sums.

We find these facts:

. .

Now you can calculate the expected value.