Thread: i cant figure this out help plz

1. i cant figure this out help plz

A box contains 1 red, 2 white and 4 blue balls. Two balls are drawn without replacement, nothing the color of each. If the first two balls drawn are white and blue in either order, then one more ball is drawn, and its color noted. Determine the number of elements in the sample space for this experiment.

2. Hello, dogfsh722!

Just make a list . . .

A box contains 1 red, 2 white and 4 blue balls. .Two balls are drawn without
replacement, noting the color of each. .If the first two balls drawn are white
and blue in either order, then one more ball is drawn, and its color noted.
Determine the number of elements in the sample space for this experiment.
Two balls are drawn. .There are eight possible outcomes:
. . $\displaystyle \{RW,\,RB,\,WR,\,WW,\,BR,\,BB\}\;\;\{WB,\,BW\}$

In the first six outcomes, the experiment is over.

In the last two outcomes, a third ball is drawn.
. . It could be $\displaystyle R,\,W\text{, or }B.$
Hence, there are: .$\displaystyle 2 \times 3 \:=\:6$ three-draw outcomes.

The number of outcomes is: .$\displaystyle \text{(6 two-draws) + (6 three-draws)} \; = \;12$