There are 5 balls in total, and 2 are black and 3 are red. If we choose with replacement, meaning we replace the ball we took out each time, what is the probability of choosing one ball of each color?

the binomial distribution says, for an experiment that can have either success of failure as an outcome

$\displaystyle p(x)=n!/x!(n-x)!p^xq^{n-x} $

n is the number of trials, x is the number of successes, p is the probability of p occurring and q=1-p

How can I set that up to solve the question of what the chance of choosing one of each ball or choosing two of the same color?