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Math Help - Probability of three dependent events

  1. #1
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    Probability of three dependent events

    We got an assignment to find such three dependent events that satisfy this equation: P(A*B*C)=P(A)*P(B)*P(C). I was thinking to solve this with use of Bayes network: A->B<-C, so P(A*B*C)=P(A)*P(B|A*C)*P(C), and with Bayes' theorem I got P(B|AC)=P(AC|B)*P(B)/P(AC)=P(B), so the first equation is true. Is this approach correct?
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  2. #2
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    Re: Probability of three dependent events

    Hey truleX.

    For this statement is P(A*B*C) = P(A and B and C)? I think that independence follows from P(A and B) = P(A)P(B) and using some induction P([A and B] and C) = P([A and B])P(C) = P(A)P(B)P(C) shows that if this is the case then A,B,C are all independent from each other (where P(A|B,C) = P(A), P(B|A,C) = P(B) and P(C|A,B) = P(C)).

    If this is not the case what does P(A*B*C) mean?
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  3. #3
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    Re: Probability of three dependent events

    Yes, * means and, + means or. I'm not sure if you understood my problem. I am dealing with three _dependent_, ie non independent events that satisfy the equation above, so I can't use rules for probability of independent events.
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  4. #4
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    Re: Probability of three dependent events

    Isn't the independence condition an if and only if statement? I am under the impression that independence and the multiplication rule are equivalent statements and the only way this can hold is if the events are independent.

    I can show you I obtain this, but I'll wait for your response.
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    Re: Probability of three dependent events

    Quote Originally Posted by truleX View Post
    We got an assignment to find such three dependent events that satisfy this equation: P(A*B*C)=P(A)*P(B)*P(C). I was thinking to solve this with use of Bayes network: A->B<-C, so P(A*B*C)=P(A)*P(B|A*C)*P(C), and with Bayes' theorem I got P(B|AC)=P(AC|B)*P(B)/P(AC)=P(B), so the first equation is true. Is this approach correct?
    Here is an example due to Glyn George.
    Attached Thumbnails Attached Thumbnails Probability of three dependent events-untitled.gif  
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  6. #6
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    Re: Probability of three dependent events

    Thank you Plato, this is exactly what I needed.
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