Hey, if anyone has time to give me some guidance on how to prove these i would be so grateful (Rock) thank you... :
i) P(A∩B) ≥ P(A) +P(B)−1,
ii) P(A∆B) = P(A) +P(B)−2P(A∩B)
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Hey, if anyone has time to give me some guidance on how to prove these i would be so grateful (Rock) thank you... :
i) P(A∩B) ≥ P(A) +P(B)−1,
ii) P(A∆B) = P(A) +P(B)−2P(A∩B)
Thanks but i don't follow/understand this. Maybe i'm hopeless but something more step by step would be great