The probability of an event and its complement equals one. True or false?
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Originally Posted by tukker0509 The probability of an event and its complement equals one. True or false? $\displaystyle \mathcal{P}(E)+\mathcal{P}(E^c)=\mathcal{P}(E)+[1-\mathcal{P}(E)]=~?$
Originally Posted by Plato $\displaystyle \mathcal{P}(E)+\mathcal{P}(E^c)=\mathcal{P}(E)+[1-\mathcal{P}(E)]=~?$ What is that equation????!
Originally Posted by jsweston828 What is that equation????! Does the OP mean $\displaystyle \mathcal{P}(E)+\mathcal{P}(E^c)$ OR $\displaystyle \mathcal{P}(E\cap E^c)~?$
Im so confused! I just answered True!!
Originally Posted by jsweston828 Im so confused! I just answered True!! Well $\displaystyle \mathcal{P}(E)+\mathcal{P}(E^c)=1$ AND $\displaystyle \mathcal{P}(E\cap E^c)=0.$
So would you say the answer is true or false!!
Originally Posted by jsweston828 So would you say the answer is true or false!! I have no idea. "The probability of an event and its complement equals one." That is such a poorly constructed phrase as to be meaningless. Look at reply #4. It could be either.
ohhh I see! Im just going to hope its correct!
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