Thread: Simple Hockey Team Probability Question

See figure attached below for the question.

I'm at a loss as to how they obtain an answer of C) for the solution. Can anyone explain this?

I was thinking of taking the odds of one underdog winning and or'ing it with the other chances of the other underdogs winning as such,

(0.43)(0.72)(0.89)(0.67)(0.82) + (0.57)(0.28)(0.89)(0.67)(0.82).... etc

Where the underdogs are in bold.

Can someone explain how to solve this question?

Hint: Pr(at least one underdog wins) = 1 - Pr(all the overdogs win)

Originally Posted by awkward

Hint: Pr(at least one underdog wins) = 1 - Pr(all the overdogs win)

Got it now! Thank you very much!