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Math Help - Simple Hockey Team Probability Question

  1. #1
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    Question Simple Hockey Team Probability Question

    See figure attached below for the question.

    I'm at a loss as to how they obtain an answer of C) for the solution. Can anyone explain this?

    I was thinking of taking the odds of one underdog winning and or'ing it with the other chances of the other underdogs winning as such,

    (0.43)(0.72)(0.89)(0.67)(0.82) + (0.57)(0.28)(0.89)(0.67)(0.82).... etc

    Where the underdogs are in bold.

    Can someone explain how to solve this question?
    Attached Thumbnails Attached Thumbnails Simple Hockey Team Probability Question-stathockq.jpg  
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  2. #2
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    Re: Simple Hockey Team Probability Question

    Hint: Pr(at least one underdog wins) = 1 - Pr(all the overdogs win)
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  3. #3
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    Re: Simple Hockey Team Probability Question

    Quote Originally Posted by awkward View Post
    Hint: Pr(at least one underdog wins) = 1 - Pr(all the overdogs win)
    Got it now! Thank you very much!
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