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Simple Hockey Team Probability Question

See figure attached below for the question.

I'm at a loss as to how they obtain an answer of C) for the solution. Can anyone explain this?

I was thinking of taking the odds of one underdog winning and or'ing it with the other chances of the other underdogs winning as such,

**(0.43)**(0.72)(0.89)(0.67)(0.82) + (0.57)**(0.28)**(0.89)(0.67)(0.82).... etc

Where **the underdogs are in bold.**

Can someone explain how to solve this question?

Re: Simple Hockey Team Probability Question

Hint: Pr(at least one underdog wins) = 1 - Pr(all the overdogs win)

Re: Simple Hockey Team Probability Question

Quote:

Originally Posted by

**awkward** Hint: Pr(at least one underdog wins) = 1 - Pr(all the overdogs win)

Got it now! Thank you very much!