What "result" are you trying to get? In other words, what question are you asking? To find "x" such that P(x< X< 9)= .2? Yes, when x= 9, z= (9- 5)/4= 1. What does your Normal Table give for the probability that z< 1? What must be subtracted from that to get 0.2? What z value corresponds to that normal probability? And what x value is that?
You say you "obtained different result". What result did you obtain?