How to write "n choose k" as x^n y^k z^(n-k) without using Stirling
Hi,
Is there a way to write the combinatorial (n choose k) as:

Without using Stirling's formula and without having a product or summation in x, y and z?
What could x=x(n,k), y=y(n,k) and z=z(n,k) be?
Thanks,
Gerrit
Re: How to write "n choose k" as x^n y^k z^(n-k) without using Stirling
Hey gerritgroot.
You may be able to use an integral representation, but the integral itself won't have a nice analytic answer if you try and evaluate it. If you are still interested, you probably want to check out the Beta Integral:
Beta function - Wikipedia, the free encyclopedia
Re: How to write "n choose k" as x^n y^k z^(n-k) without using Stirling
Thanks, I will check that