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Math Help - ANOVA chapter..... 2 problems , one anwered - did I do it correctly? one no clue

  1. #1
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    ANOVA chapter..... 2 problems , one anwered - did I do it correctly? one no clue

    I actually have two problems - the first I have attempted to figure out, but not sure I have it correcct. Still don't understand how to interpret the answer I get.


    A Stockbrocker at Critical Securities reported that the mean rate of return on a sample of 10 oil stocks was 12.6 percent with a satnadard deviation of 3.9 percent. The mean rate of return on a sample of 8 utility stocks was 10.9 percent with a standard deviation of 3.5 percent. At the .05 significance level, can we conclude that there is more variation in the oil stocks?

    I have F=3.9^/3.5^ =1.2416
    n1 - 1, n2 - 1 = 9,7
    Critical F value =3.667
    Reject if F 3.667 ???
    1.2416 < 3.667 so fail to reject?

    Did I calculate correctly - and how does that result translate to answer is there more variation?

    This next problem - need help on set up and interpretation.


    The following is sample information. Test the hypothesis at the .05 significance level that the treatment means are equal.

    Treatment 1
    9,7,11,9,12,10

    Treatment 2
    13,20,14,13,

    Treatment 3
    10,9,15,14,15,

    a.State the null hypothesis and the alternate hypotheses.
    b.What is the decision rule?
    c.Compute SST, SSE, and SS total.
    d.Complete an ANOVA table.
    e.State your decision regarding the null hypothesis.
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    Re: ANOVA chapter..... 2 problems , one anwered - did I do it correctly? one no clue

    Quote Originally Posted by cama62 View Post
    I have F=3.9^/3.5^ =1.2416
    n1 - 1, n2 - 1 = 9,7
    Critical F value =3.667
    Reject if F 3.667 ???
    1.2416 < 3.667 so fail to reject?
    Yes, if your calculated F-value is less than your critical F-value then fail to reject the null hypothesis.
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    Lightbulb Re: ANOVA chapter..... 2 problems , one anwered - did I do it correctly? one no clue


    T1<>T2 (p<0.05)
    T1=T3 (p>0.05)
    T2=T3 (p>0.05)
    Attached Files Attached Files
    Last edited by MaxJasper; October 3rd 2012 at 07:09 PM.
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    Senior Member MaxJasper's Avatar
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    Lightbulb Re: ANOVA chapter..... 2 problems , one anwered - did I do it correctly? one no clue

    P_f\left[\frac{3.9^2}{3.5^2}|\nu _1=9,\nu _2=7\right]=0.60356>.05 Can't reject equal variance hypothesis.
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