1. ## The normal distribution

I have a Probability question from about a year ago, involving the normal distribution, which I answered but I lost the paper my answer was on, until now. I have finally found it, but now that I'm looking over my answer from a year ago, I see that there are no formulas and certainly no normal distribution table to support my answer. Would someone please be able to help me with this? I need to know what the normal distribution table will look like to support my working and where to put the formulas into my equations.

The normal distribution
Give clear explanations and show all working. You must provide a diagram and correct probability statements for the question.

The weights of newborn babies in Battland are normally distributed with a mean of 3.43 kg and standard deviation of 0.36 kg.

1% of newborn babies are classed as low birthweight babies and often in need of special care. What weight is defined as low birthweight in Battland?

Working:
3.43 - (0.36 x 3)
= 2.35

2.35 - 3.43 divided by 0.6 = 0.4987

0.5 - 0.4987 = 0.0026

0.5 - 0.0026 = 0.4974
z = 2.79

0.36 x 2.79 = 1.0044

3.43 - 1.0044 = 2.4256
= 2.43
So, 2.43 kg is defined as low birthweight in Battland

2. Originally Posted by Kiwigirl
I have a Probability question from about a year ago, involving the normal distribution, which I answered but I lost the paper my answer was on, until now. I have finally found it, but now that I'm looking over my answer from a year ago, I see that there are no formulas and certainly no normal distribution table to support my answer. Would someone please be able to help me with this? I need to know what the normal distribution table will look like to support my working and where to put the formulas into my equations.

The normal distribution
Give clear explanations and show all working. You must provide a diagram and correct probability statements for the question.

The weights of newborn babies in Battland are normally distributed with a mean of 3.43 kg and standard deviation of 0.36 kg.

1% of newborn babies are classed as low birthweight babies and often in need of special care. What weight is defined as low birthweight in Battland?

Working:
3.43 - (0.36 x 3)
= 2.35

2.35 - 3.43 divided by 0.6 = 0.4987

0.5 - 0.4987 = 0.0026

0.5 - 0.0026 = 0.4974
z = 2.79

0.36 x 2.79 = 1.0044

3.43 - 1.0044 = 2.4256
= 2.43
So, 2.43 kg is defined as low birthweight in Battland
Please do not make double posts on the forums.

3. I'm really sorry about making the double post, I thought I was allowed to as long as it was in a different forum but obviously I now know I can't. But how do I make the diagram fit my answer? Also, do you know where to put the formula into my equations? Formula: z = (x - mean) divided by standard deviation.

4. Originally Posted by Kiwigirl
I have a Probability question from about a year ago, involving the normal distribution, which I answered but I lost the paper my answer was on, until now. I have finally found it, but now that I'm looking over my answer from a year ago, I see that there are no formulas and certainly no normal distribution table to support my answer. Would someone please be able to help me with this? I need to know what the normal distribution table will look like to support my working and where to put the formulas into my equations.

The normal distribution
Give clear explanations and show all working. You must provide a diagram and correct probability statements for the question.

The weights of newborn babies in Battland are normally distributed with a mean of 3.43 kg
and standard deviation of 0.36 kg.

1% of newborn babies are classed as low birthweight babies and often in need of special care. What weight is defined as low birthweight in Battland?
As 1% of newborns are classed as low birth weight, then all babies of
birth weight < the first percentile of a normal distribution with mean 3.43
and standard deviation 0.36 kg are classed as of low birth weight.

But if denotes the $b$ is the birth weight of a child, then:

$
z=\frac{b-\mbox{mean birth weight}}{\mbox{standard Dev of birth weight}}
$

has a standard normal distribution (as $b$ is normally distributed),
and a newborn is classed as of low birth weight if $z$is less than
the first percentile of a standard normal distribution.

Looking up the first percentile (0.01 value) in a table of the standard
normal distribution gives a value of -2.32679 or about -2.33. So a baby is
of low birth weight if:

$
z=\frac{b-3.43}{0.36}<-2.33
$

or rearranging:

$
b<(-2.33 \times 0.36)+3.43\approx 2.59\ \mbox{kg}
$

RonL

Thanks for that, you've helped me twice now, and your last explanation was excellent. I realise that I must seem dense, but probability has never been my speciality. I am still uncertain how to go about the normal distribution table and I don't quite understand your explanation this time, would you be able to simplify this so that I can have a better understanding of how to answer this with the formula? You have become a great help to me, thanks again

6. Originally Posted by Kiwigirl
Thanks for that, you've helped me twice now, and your last explanation was excellent. I realise that I must seem dense, but probability has never been my speciality. I am still uncertain how to go about the normal distribution table and I don't quite understand your explanation this time, would you be able to simplify this so that I can have a better understanding of how to answer this with the formula? You have become a great help to me, thanks again
First, you need to know that if $b$ is normally distributed with mean $m$, and
standard deviation $s$, that:

$
z=\frac{b-m}{s}
$

is normally distributed with mean $0$ and standard deviation $1$. The normal
distribution with mean $0$ and standard deviation $1$ is called the standard
normal distribution.

Tables of the normal distribution are always for the standard normal
distribution, which is why we transform from the meaningfully variable
$b$ to the slightly obscure variable $z$, so we can use the tabulated
values of the standard normal distribution.

Then a probability like: $P(b<2.7)=p$ can we written as an equivalent
statement about $z$: $P(z<(2.7-m)/s)=p$.

Now the use of normal distribution table to find something like the value $r$ such that:

$
P(z$

can be tricky to explain, mainly because the format of the tables varies
so much depending on the source of the table. I think I should leave
such an explanation to a more authoritative source, like the:
Engineering Stats Handbook

RonL