Hi every ones,

First, I an an old folk that have completed some statistics classes 25 years ago. But now, I am to rusty to solve this by myself. ( However, I tried).

And I really need an answer. Your help would be appreciated.

Here is the problem:

A computer update its clock once every 1xE-8 seconds. Therefore, 3.1536xE15 times per years.

So, since the computer update its time every 1xE-8 seconds, if two events happen into this interval of time,the computer will see them as being simultaneous.

This computer receive some information requests and it takes about 2xE-3 second to process each one of them (However, it can be some minutes, between each request)

1) The computer cannot process more than 1 request at the time.

2) Each time that the computer receive a request, it records the time where the request was received and puts a "time stamp" on the request.

request can be received at any time during a day, but:

the probability for a request to be received at certain time during the day is as follow:

-Between 8:00 and 17:00, = 0.801 with equal probability at any time of this interval (ie: 80.1% are received in this interval)

-Between 17:00 and 21:00, = 0.177 with equal probability at any time of this interval (ie: 17.7% are received in this interval)

-Between 21:00 and 8:00, = 0.022 with equal probability at any time of this interval (ie: 2.2% are received in this interval)

The computer will receive "X" requests each year

NOW:

Assuming that we have "Y" computers receiving requests (each one of them receiving "X" requests every year), what is the probability that 2 requests, or more, gets the same "Time Stamp" at the end of the year(In other words: that two computers, or more, have received request simultaneously during the year)