Hi every ones,
First, I an an old folk that have completed some statistics classes 25 years ago. But now, I am to rusty to solve this by myself. ( However, I tried).
And I really need an answer. Your help would be appreciated.
Here is the problem:
A computer update its clock once every 1xE-8 seconds. Therefore, 3.1536xE15 times per years.
So, since the computer update its time every 1xE-8 seconds, if two events happen into this interval of time,the computer will see them as being simultaneous.
This computer receive some information requests and it takes about 2xE-3 second to process each one of them (However, it can be some minutes, between each request)
1) The computer cannot process more than 1 request at the time.
2) Each time that the computer receive a request, it records the time where the request was received and puts a "time stamp" on the request.
request can be received at any time during a day, but:
the probability for a request to be received at certain time during the day is as follow:
-Between 8:00 and 17:00, = 0.801 with equal probability at any time of this interval (ie: 80.1% are received in this interval)
-Between 17:00 and 21:00, = 0.177 with equal probability at any time of this interval (ie: 17.7% are received in this interval)
-Between 21:00 and 8:00, = 0.022 with equal probability at any time of this interval (ie: 2.2% are received in this interval)
The computer will receive "X" requests each year
Assuming that we have "Y" computers receiving requests (each one of them receiving "X" requests every year), what is the probability that 2 requests, or more, gets the same "Time Stamp" at the end of the year(In other words: that two computers, or more, have received request simultaneously during the year)