As far as the method of calculating the mean is concerned the two questions are the same.

By the way you should not use E in place of .

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- September 15th 2012, 10:53 PM #1

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## Question.

I am somewhat confused on these 2. I want to know what the difference is in finding the mean. For one means, I did 4(0.0537)+5(0.1124)+6(.1473) and etc. For the other problem, to find he mean, you have to multiply, it was more like 0(0.0776);1(.103); 2(.047) and etc. I am just wondering the term I have to really look out for when I look for the mean in these 2 problems. Meaning, when are the times I have to add abd tge other times I have to multiply.

P.S. I know I can just input this in my TI84 and get the answers quickly, but I am more curious by putting it on paper.

I also know the rule is u=E[X.P(X)]

- September 16th 2012, 01:01 AM #2

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- September 16th 2012, 01:53 PM #3

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- September 16th 2012, 02:06 PM #4

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- September 16th 2012, 02:48 PM #5

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## Re: Question.

See, the first one, has 4.0.0537

**+**5. 0.1124 and then does 6+ etc, 7+... The second problem there is no plus, it's all multiplication until you add all of them up. Because it looks like 1.0.103= 0.103.. Then it's 2 . etc... There is no addition between those numbers. Get what I am saying? Sorry if it sounds confusing.

- September 16th 2012, 03:26 PM #6

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