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Math Help - Question.

  1. #1
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    Question.

    I am somewhat confused on these 2. I want to know what the difference is in finding the mean. For one means, I did 4(0.0537)+5(0.1124)+6(.1473) and etc. For the other problem, to find he mean, you have to multiply, it was more like 0(0.0776);1(.103); 2(.047) and etc. I am just wondering the term I have to really look out for when I look for the mean in these 2 problems. Meaning, when are the times I have to add abd tge other times I have to multiply.

    P.S. I know I can just input this in my TI84 and get the answers quickly, but I am more curious by putting it on paper.

    I also know the rule is u=E[X.P(X)]
    Attached Thumbnails Attached Thumbnails Question.-q2.png   Question.-q1.png  
    Last edited by Past45; September 15th 2012 at 10:59 PM.
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  2. #2
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    Re: Question.

    As far as the method of calculating the mean is concerned the two questions are the same.

    By the way you should not use E in place of \Sigma.
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  3. #3
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    Re: Question.

    Actually the calculations seem a bit different, as for the follow attachments. Finding the mean seem a little different.
    Attached Thumbnails Attached Thumbnails Question.-q13.png   Question.-q12.png  
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  4. #4
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    Re: Question.

    Look at the calculation in the third column. It's the same.
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  5. #5
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    Re: Question.

    Quote Originally Posted by a tutor View Post
    Look at the calculation in the third column. It's the same.
    See, the first one, has 4.0.0537+ 5. 0.1124 and then does 6+ etc, 7+... The second problem there is no plus, it's all multiplication until you add all of them up. Because it looks like 1.0.103= 0.103.. Then it's 2 . etc... There is no addition between those numbers. Get what I am saying? Sorry if it sounds confusing.
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  6. #6
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    Re: Question.

    Quote Originally Posted by Past45 View Post
    The second problem there is no plus, it's all multiplication until you add all of them up.
    Trust me, it's the same as the other one.
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