25/400 = prob 1st winner
24/399 = prob 2nd winner
23/398 = ....
22/397
.....
1/375
Each winner's name out of the box is not replaced into the box again so his name is not drawn 1,2,3,4,5,... times...only once and he goes home right away!
Hello everyone!
I have a probability problem, that I can not seem to be able to figure the exact answer for. So I'm hoping that someone here could help me out.
The problem:
This is for a lottery drawing. There are 4 drawings. During each drawing 100 finalists are being picked at random. Each person can only be selected once in each of the 4 drawings. Then, there is a final drawing, where out of the 400 finalists, 25 are randomly picked to be awarded different prizes. In the final drawing, each person selected can only win once. If they are selected, they're out of the pool and the drawing continues with the remaining finalists until all 25 prizes are awarded. I would like to figure out how the likelihood of being picked changes if one has their name for the final drawing 1 time, 2 times, 3 times, 4 times. If someone could help me come out with some sort of formula for it, I would greatly appreciate it.
Thank you very much in advance!
25/400 = prob 1st winner
24/399 = prob 2nd winner
23/398 = ....
22/397
.....
1/375
Each winner's name out of the box is not replaced into the box again so his name is not drawn 1,2,3,4,5,... times...only once and he goes home right away!