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Math Help - OMG please help! (standard deviation)

  1. #1
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    OMG please help! (standard deviation)

    3 instructors are comparing scores on their finals; each has 99 students. Class A:, one student got 1 point, another got 99 points, and the rest 50 points. Class B: 49 students got a score of 1. one student got a score of 50, and 49 students got a score of 99. Class C: one student got a score of 1, one student got a score of 2, one student got a score of 3, and so forth, all the way through 99.

    Im trying to find the average of each. I got class A & B, but cant figure out how to calculate C!

    Class A: (1x1) (1x99) (97x50)= 1+99+4850 = 4950/99 = 50

    Class B: (1x49) (1x50) (49x99) = 49+50+4851 =4950/99 = 50

    Class C: (1x1) (1x2) (1x3)......???

    I could write it all out but that would take forever...any easier way?

    Help is greatly appreciated!
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  2. #2
    MHF Contributor
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    Re: OMG please help! (standard deviation)

    Karl Friedrich Gauss has figured this out for you.
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