if someone have 4 red bricks and 8 blue bricks ,he want to arrange them randomly in circular shape, What is the probability that two red bricks are not side by side?
Hello, Mhmh96!
If someone have 4 red bricks and 8 blue bricks and arranges them randomly in a circle,
what is the probability that two red bricks are not side by side?
There are possible arrangements.
(This includes duplication from rotations.)
Place the 8 blue bricks in a circle, leaving a space between them.
. .
Select 4 of the 8 spaces and insert the red bricks.
There are: ways.
Therefore: .