cumulative distribution function problem
I have this question I am trying to get through but i keep coming into trouble. The question is:
Show that the cumulative distribution function from a uniform distribution of the random variable is Fx(y) = (y-a) / (b-a) for some a < y < b
I've started the question but have become stuck going from here
y
∫ x/(b-a) dx
a
when i integrate i come up with y2-a2/2(b-a). When i'm pretty sure it should come out as (y/b-a)-(a/b-a) which would then solve to y-a/b-a
any advice as to what i'm forgetting to do would help me alot, thanks.
Re: cumulative distribution function problem
Quote:
Originally Posted by
bryce09
Show that the cumulative distribution function from a uniform distribution of the random variable is Fx(y) = (y-a) / (b-a) for some a < y < b
I've started the question but have become stuck going from here
y
∫ x/(b-a) dx
You want to start with $\displaystyle \int_a^y {\frac{{dx}}{{b - a}}}~.$
Re: cumulative distribution function problem
Ok that makes sense, so the dx just integrates to x doesn't it. which then goes into y-a/1.
Silly question, but why is it that there is no x, and just dx?